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Q: Two digit is 3 less than 7 times the sum its digit if the digit reversed the new number is less than the original number what is the number?

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There are 4 possible answers: 32, 53, 74 and 95.

The number is 36

100000 2847239582

45

2178 * 4 = 8712

81.

To begin with, let's represent the ten's digit with x. Then, we know that the one's digit is (10-x), because the sum of the digits is 10. Since the value of the ten's is 10 times more than the digit, we multiply it by 10. Now we have the original number: 10x+10-x. We can simplify it into 9x+10. For the reversed number, the digits switch spots, so now we multiply the one's by 10. The reversed # is 10(10-x)+x, which could be simplified into 100-9x.To get an equation you have to balance the two sides. For that, you need to add 18 to the original # to make it equal to the reversed #.9x+10+18=100-9x9x+9x=100-2818x=82x=82/18x=4The original number is 46.The reversed number is 64.CHECK: 64-46=18IT WORKS!!!

13213

1089! times 9 is 9801. I'm really bored.

It is 58.

The number must meet two criteria:Take the original number excluding its last digit and subtract two times the last digit from it. The result must be divisible by 7.Take the original number excluding its last digit and subtract nine times the last digit from it. The result must be divisible by 13.In both cases, you can repeat the "truncate-and-subtract multiple" stage several times, if required.

There is no such two digit number. If the first digit is x and the second is y, then the number is 10x + y, its digit reverse is 10y + x, and: 10x + y + 8 = 10y + x → 9x + 8 = 9y → 9x + 8 = 18x → 9x = 8 → x = 9/8 BUT x must be a whole number.as x is a digit 1-9. ergo the problem as stated has no solution.

2178

Yes because 8 times 225 = 1800 ------------------------------------------------------------------------------------------ To check for divisibility by 8 (ie whether a number is in the 8 times table): add the four times the hundreds digit to twice the tens digit to the ones digit; if this sum is divisible by 8, then so is the original number (and so the original number is in the 8 times table). For 1800 this gives 4 × 8 + 2 × 0 + 0 = 32 = 4 × 8, therefore 1800 is divisible by 8 (and thus in the 8 times table).

6 times

25 does.(25 x 2) + 2 = 50 + 2 = 52

i am a two digit # my tens digit# is 3 times my ones digit #and the sum of my digit is 12 what am i

it can't be possible for an answer because 13 is not a product of anything so if you do math you are going to have some remainders which means that the complete digit is not possible

285

60x2

2

93

-- Nothing happens to it. -- You generate a new number that's ten times the size of the original number. -- The new number has all the same digits as the original number had, in the same order. But the decimal point in the new number is one digit to the right of where it was in the original number.

It is 63.

The digit (not didgit) 1.